3.87 \(\int x^3 \sin ^{-1}(a x)^{5/2} \, dx\)

Optimal. Leaf size=205 \[ \frac {15 \sqrt {\frac {\pi }{2}} C\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{4096 a^4}-\frac {15 \sqrt {\pi } C\left (\frac {2 \sqrt {\sin ^{-1}(a x)}}{\sqrt {\pi }}\right )}{256 a^4}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {225 \sqrt {\sin ^{-1}(a x)}}{2048 a^4}-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)} \]

[Out]

-3/32*arcsin(a*x)^(5/2)/a^4+1/4*x^4*arcsin(a*x)^(5/2)+15/8192*FresnelC(2*2^(1/2)/Pi^(1/2)*arcsin(a*x)^(1/2))*2
^(1/2)*Pi^(1/2)/a^4-15/256*FresnelC(2*arcsin(a*x)^(1/2)/Pi^(1/2))*Pi^(1/2)/a^4+15/64*x*arcsin(a*x)^(3/2)*(-a^2
*x^2+1)^(1/2)/a^3+5/32*x^3*arcsin(a*x)^(3/2)*(-a^2*x^2+1)^(1/2)/a+225/2048*arcsin(a*x)^(1/2)/a^4-45/256*x^2*ar
csin(a*x)^(1/2)/a^2-15/256*x^4*arcsin(a*x)^(1/2)

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Rubi [A]  time = 0.60, antiderivative size = 205, normalized size of antiderivative = 1.00, number of steps used = 18, number of rules used = 7, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {4629, 4707, 4641, 4723, 3312, 3304, 3352} \[ \frac {15 \sqrt {\frac {\pi }{2}} \text {FresnelC}\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{4096 a^4}-\frac {15 \sqrt {\pi } \text {FresnelC}\left (\frac {2 \sqrt {\sin ^{-1}(a x)}}{\sqrt {\pi }}\right )}{256 a^4}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {225 \sqrt {\sin ^{-1}(a x)}}{2048 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)} \]

Antiderivative was successfully verified.

[In]

Int[x^3*ArcSin[a*x]^(5/2),x]

[Out]

(225*Sqrt[ArcSin[a*x]])/(2048*a^4) - (45*x^2*Sqrt[ArcSin[a*x]])/(256*a^2) - (15*x^4*Sqrt[ArcSin[a*x]])/256 + (
15*x*Sqrt[1 - a^2*x^2]*ArcSin[a*x]^(3/2))/(64*a^3) + (5*x^3*Sqrt[1 - a^2*x^2]*ArcSin[a*x]^(3/2))/(32*a) - (3*A
rcSin[a*x]^(5/2))/(32*a^4) + (x^4*ArcSin[a*x]^(5/2))/4 + (15*Sqrt[Pi/2]*FresnelC[2*Sqrt[2/Pi]*Sqrt[ArcSin[a*x]
]])/(4096*a^4) - (15*Sqrt[Pi]*FresnelC[(2*Sqrt[ArcSin[a*x]])/Sqrt[Pi]])/(256*a^4)

Rule 3304

Int[sin[Pi/2 + (e_.) + (f_.)*(x_)]/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[Cos[(f*x^2)/d],
x], x, Sqrt[c + d*x]], x] /; FreeQ[{c, d, e, f}, x] && ComplexFreeQ[f] && EqQ[d*e - c*f, 0]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 3352

Int[Cos[(d_.)*((e_.) + (f_.)*(x_))^2], x_Symbol] :> Simp[(Sqrt[Pi/2]*FresnelC[Sqrt[2/Pi]*Rt[d, 2]*(e + f*x)])/
(f*Rt[d, 2]), x] /; FreeQ[{d, e, f}, x]

Rule 4629

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_)*(x_)^(m_.), x_Symbol] :> Simp[(x^(m + 1)*(a + b*ArcSin[c*x])^n)/(m
+ 1), x] - Dist[(b*c*n)/(m + 1), Int[(x^(m + 1)*(a + b*ArcSin[c*x])^(n - 1))/Sqrt[1 - c^2*x^2], x], x] /; Fre
eQ[{a, b, c}, x] && IGtQ[m, 0] && GtQ[n, 0]

Rule 4641

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[(a + b*ArcSin[c*x])^
(n + 1)/(b*c*Sqrt[d]*(n + 1)), x] /; FreeQ[{a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && GtQ[d, 0] && NeQ[n,
-1]

Rule 4707

Int[(((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol] :> Simp[
(f*(f*x)^(m - 1)*Sqrt[d + e*x^2]*(a + b*ArcSin[c*x])^n)/(e*m), x] + (Dist[(f^2*(m - 1))/(c^2*m), Int[((f*x)^(m
- 2)*(a + b*ArcSin[c*x])^n)/Sqrt[d + e*x^2], x], x] + Dist[(b*f*n*Sqrt[1 - c^2*x^2])/(c*m*Sqrt[d + e*x^2]), I
nt[(f*x)^(m - 1)*(a + b*ArcSin[c*x])^(n - 1), x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && EqQ[c^2*d + e, 0] &&
GtQ[n, 0] && GtQ[m, 1] && IntegerQ[m]

Rule 4723

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[d^p/c^(
m + 1), Subst[Int[(a + b*x)^n*Sin[x]^m*Cos[x]^(2*p + 1), x], x, ArcSin[c*x]], x] /; FreeQ[{a, b, c, d, e, n},
x] && EqQ[c^2*d + e, 0] && IntegerQ[2*p] && GtQ[p, -1] && IGtQ[m, 0] && (IntegerQ[p] || GtQ[d, 0])

Rubi steps

\begin {align*} \int x^3 \sin ^{-1}(a x)^{5/2} \, dx &=\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}-\frac {1}{8} (5 a) \int \frac {x^4 \sin ^{-1}(a x)^{3/2}}{\sqrt {1-a^2 x^2}} \, dx\\ &=\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}-\frac {15}{64} \int x^3 \sqrt {\sin ^{-1}(a x)} \, dx-\frac {15 \int \frac {x^2 \sin ^{-1}(a x)^{3/2}}{\sqrt {1-a^2 x^2}} \, dx}{32 a}\\ &=-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}-\frac {15 \int \frac {\sin ^{-1}(a x)^{3/2}}{\sqrt {1-a^2 x^2}} \, dx}{64 a^3}-\frac {45 \int x \sqrt {\sin ^{-1}(a x)} \, dx}{128 a^2}+\frac {1}{512} (15 a) \int \frac {x^4}{\sqrt {1-a^2 x^2} \sqrt {\sin ^{-1}(a x)}} \, dx\\ &=-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}+\frac {15 \operatorname {Subst}\left (\int \frac {\sin ^4(x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{512 a^4}+\frac {45 \int \frac {x^2}{\sqrt {1-a^2 x^2} \sqrt {\sin ^{-1}(a x)}} \, dx}{512 a}\\ &=-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}+\frac {15 \operatorname {Subst}\left (\int \left (\frac {3}{8 \sqrt {x}}-\frac {\cos (2 x)}{2 \sqrt {x}}+\frac {\cos (4 x)}{8 \sqrt {x}}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{512 a^4}+\frac {45 \operatorname {Subst}\left (\int \frac {\sin ^2(x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{512 a^4}\\ &=\frac {45 \sqrt {\sin ^{-1}(a x)}}{2048 a^4}-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}+\frac {15 \operatorname {Subst}\left (\int \frac {\cos (4 x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{4096 a^4}-\frac {15 \operatorname {Subst}\left (\int \frac {\cos (2 x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{1024 a^4}+\frac {45 \operatorname {Subst}\left (\int \left (\frac {1}{2 \sqrt {x}}-\frac {\cos (2 x)}{2 \sqrt {x}}\right ) \, dx,x,\sin ^{-1}(a x)\right )}{512 a^4}\\ &=\frac {225 \sqrt {\sin ^{-1}(a x)}}{2048 a^4}-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}+\frac {15 \operatorname {Subst}\left (\int \cos \left (4 x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{2048 a^4}-\frac {15 \operatorname {Subst}\left (\int \cos \left (2 x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{512 a^4}-\frac {45 \operatorname {Subst}\left (\int \frac {\cos (2 x)}{\sqrt {x}} \, dx,x,\sin ^{-1}(a x)\right )}{1024 a^4}\\ &=\frac {225 \sqrt {\sin ^{-1}(a x)}}{2048 a^4}-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}+\frac {15 \sqrt {\frac {\pi }{2}} C\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{4096 a^4}-\frac {15 \sqrt {\pi } C\left (\frac {2 \sqrt {\sin ^{-1}(a x)}}{\sqrt {\pi }}\right )}{1024 a^4}-\frac {45 \operatorname {Subst}\left (\int \cos \left (2 x^2\right ) \, dx,x,\sqrt {\sin ^{-1}(a x)}\right )}{512 a^4}\\ &=\frac {225 \sqrt {\sin ^{-1}(a x)}}{2048 a^4}-\frac {45 x^2 \sqrt {\sin ^{-1}(a x)}}{256 a^2}-\frac {15}{256} x^4 \sqrt {\sin ^{-1}(a x)}+\frac {15 x \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{64 a^3}+\frac {5 x^3 \sqrt {1-a^2 x^2} \sin ^{-1}(a x)^{3/2}}{32 a}-\frac {3 \sin ^{-1}(a x)^{5/2}}{32 a^4}+\frac {1}{4} x^4 \sin ^{-1}(a x)^{5/2}+\frac {15 \sqrt {\frac {\pi }{2}} C\left (2 \sqrt {\frac {2}{\pi }} \sqrt {\sin ^{-1}(a x)}\right )}{4096 a^4}-\frac {15 \sqrt {\pi } C\left (\frac {2 \sqrt {\sin ^{-1}(a x)}}{\sqrt {\pi }}\right )}{256 a^4}\\ \end {align*}

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Mathematica [C]  time = 0.04, size = 140, normalized size = 0.68 \[ \frac {\sqrt {\sin ^{-1}(a x)} \left (16 \sqrt {2} \sqrt {i \sin ^{-1}(a x)} \Gamma \left (\frac {7}{2},-2 i \sin ^{-1}(a x)\right )+16 \sqrt {2} \sqrt {-i \sin ^{-1}(a x)} \Gamma \left (\frac {7}{2},2 i \sin ^{-1}(a x)\right )-\sqrt {i \sin ^{-1}(a x)} \Gamma \left (\frac {7}{2},-4 i \sin ^{-1}(a x)\right )-\sqrt {-i \sin ^{-1}(a x)} \Gamma \left (\frac {7}{2},4 i \sin ^{-1}(a x)\right )\right )}{2048 a^4 \sqrt {\sin ^{-1}(a x)^2}} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[x^3*ArcSin[a*x]^(5/2),x]

[Out]

(Sqrt[ArcSin[a*x]]*(16*Sqrt[2]*Sqrt[I*ArcSin[a*x]]*Gamma[7/2, (-2*I)*ArcSin[a*x]] + 16*Sqrt[2]*Sqrt[(-I)*ArcSi
n[a*x]]*Gamma[7/2, (2*I)*ArcSin[a*x]] - Sqrt[I*ArcSin[a*x]]*Gamma[7/2, (-4*I)*ArcSin[a*x]] - Sqrt[(-I)*ArcSin[
a*x]]*Gamma[7/2, (4*I)*ArcSin[a*x]]))/(2048*a^4*Sqrt[ArcSin[a*x]^2])

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*arcsin(a*x)^(5/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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giac [C]  time = 0.31, size = 297, normalized size = 1.45 \[ \frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (4 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} - \frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (2 i \, \arcsin \left (a x\right )\right )}}{16 \, a^{4}} - \frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (-2 i \, \arcsin \left (a x\right )\right )}}{16 \, a^{4}} + \frac {\arcsin \left (a x\right )^{\frac {5}{2}} e^{\left (-4 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} + \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (4 i \, \arcsin \left (a x\right )\right )}}{512 \, a^{4}} - \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (2 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} + \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (-2 i \, \arcsin \left (a x\right )\right )}}{64 \, a^{4}} - \frac {5 i \, \arcsin \left (a x\right )^{\frac {3}{2}} e^{\left (-4 i \, \arcsin \left (a x\right )\right )}}{512 \, a^{4}} - \frac {\left (15 i + 15\right ) \, \sqrt {2} \sqrt {\pi } \operatorname {erf}\left (\left (i - 1\right ) \, \sqrt {2} \sqrt {\arcsin \left (a x\right )}\right )}{32768 \, a^{4}} + \frac {\left (15 i - 15\right ) \, \sqrt {2} \sqrt {\pi } \operatorname {erf}\left (-\left (i + 1\right ) \, \sqrt {2} \sqrt {\arcsin \left (a x\right )}\right )}{32768 \, a^{4}} + \frac {\left (15 i + 15\right ) \, \sqrt {\pi } \operatorname {erf}\left (\left (i - 1\right ) \, \sqrt {\arcsin \left (a x\right )}\right )}{1024 \, a^{4}} - \frac {\left (15 i - 15\right ) \, \sqrt {\pi } \operatorname {erf}\left (-\left (i + 1\right ) \, \sqrt {\arcsin \left (a x\right )}\right )}{1024 \, a^{4}} - \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (4 i \, \arcsin \left (a x\right )\right )}}{4096 \, a^{4}} + \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (2 i \, \arcsin \left (a x\right )\right )}}{256 \, a^{4}} + \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (-2 i \, \arcsin \left (a x\right )\right )}}{256 \, a^{4}} - \frac {15 \, \sqrt {\arcsin \left (a x\right )} e^{\left (-4 i \, \arcsin \left (a x\right )\right )}}{4096 \, a^{4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*arcsin(a*x)^(5/2),x, algorithm="giac")

[Out]

1/64*arcsin(a*x)^(5/2)*e^(4*I*arcsin(a*x))/a^4 - 1/16*arcsin(a*x)^(5/2)*e^(2*I*arcsin(a*x))/a^4 - 1/16*arcsin(
a*x)^(5/2)*e^(-2*I*arcsin(a*x))/a^4 + 1/64*arcsin(a*x)^(5/2)*e^(-4*I*arcsin(a*x))/a^4 + 5/512*I*arcsin(a*x)^(3
/2)*e^(4*I*arcsin(a*x))/a^4 - 5/64*I*arcsin(a*x)^(3/2)*e^(2*I*arcsin(a*x))/a^4 + 5/64*I*arcsin(a*x)^(3/2)*e^(-
2*I*arcsin(a*x))/a^4 - 5/512*I*arcsin(a*x)^(3/2)*e^(-4*I*arcsin(a*x))/a^4 - (15/32768*I + 15/32768)*sqrt(2)*sq
rt(pi)*erf((I - 1)*sqrt(2)*sqrt(arcsin(a*x)))/a^4 + (15/32768*I - 15/32768)*sqrt(2)*sqrt(pi)*erf(-(I + 1)*sqrt
(2)*sqrt(arcsin(a*x)))/a^4 + (15/1024*I + 15/1024)*sqrt(pi)*erf((I - 1)*sqrt(arcsin(a*x)))/a^4 - (15/1024*I -
15/1024)*sqrt(pi)*erf(-(I + 1)*sqrt(arcsin(a*x)))/a^4 - 15/4096*sqrt(arcsin(a*x))*e^(4*I*arcsin(a*x))/a^4 + 15
/256*sqrt(arcsin(a*x))*e^(2*I*arcsin(a*x))/a^4 + 15/256*sqrt(arcsin(a*x))*e^(-2*I*arcsin(a*x))/a^4 - 15/4096*s
qrt(arcsin(a*x))*e^(-4*I*arcsin(a*x))/a^4

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maple [A]  time = 0.10, size = 154, normalized size = 0.75 \[ -\frac {1024 \arcsin \left (a x \right )^{\frac {5}{2}} \cos \left (2 \arcsin \left (a x \right )\right ) \sqrt {\pi }-256 \arcsin \left (a x \right )^{\frac {5}{2}} \cos \left (4 \arcsin \left (a x \right )\right ) \sqrt {\pi }-1280 \arcsin \left (a x \right )^{\frac {3}{2}} \sin \left (2 \arcsin \left (a x \right )\right ) \sqrt {\pi }+160 \arcsin \left (a x \right )^{\frac {3}{2}} \sin \left (4 \arcsin \left (a x \right )\right ) \sqrt {\pi }-15 \pi \FresnelC \left (\frac {2 \sqrt {2}\, \sqrt {\arcsin \left (a x \right )}}{\sqrt {\pi }}\right ) \sqrt {2}-960 \sqrt {\arcsin \left (a x \right )}\, \sqrt {\pi }\, \cos \left (2 \arcsin \left (a x \right )\right )+480 \pi \FresnelC \left (\frac {2 \sqrt {\arcsin \left (a x \right )}}{\sqrt {\pi }}\right )+60 \cos \left (4 \arcsin \left (a x \right )\right ) \sqrt {\arcsin \left (a x \right )}\, \sqrt {\pi }}{8192 a^{4} \sqrt {\pi }} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*arcsin(a*x)^(5/2),x)

[Out]

-1/8192/a^4/Pi^(1/2)*(1024*arcsin(a*x)^(5/2)*cos(2*arcsin(a*x))*Pi^(1/2)-256*arcsin(a*x)^(5/2)*cos(4*arcsin(a*
x))*Pi^(1/2)-1280*arcsin(a*x)^(3/2)*sin(2*arcsin(a*x))*Pi^(1/2)+160*arcsin(a*x)^(3/2)*sin(4*arcsin(a*x))*Pi^(1
/2)-15*Pi*FresnelC(2*2^(1/2)/Pi^(1/2)*arcsin(a*x)^(1/2))*2^(1/2)-960*arcsin(a*x)^(1/2)*Pi^(1/2)*cos(2*arcsin(a
*x))+480*Pi*FresnelC(2*arcsin(a*x)^(1/2)/Pi^(1/2))+60*cos(4*arcsin(a*x))*arcsin(a*x)^(1/2)*Pi^(1/2))

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*arcsin(a*x)^(5/2),x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: Error executing code in Maxima: expt: undefined: 0 to a negative e
xponent.

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x^3\,{\mathrm {asin}\left (a\,x\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*asin(a*x)^(5/2),x)

[Out]

int(x^3*asin(a*x)^(5/2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{3} \operatorname {asin}^{\frac {5}{2}}{\left (a x \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*asin(a*x)**(5/2),x)

[Out]

Integral(x**3*asin(a*x)**(5/2), x)

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